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關(guān)注：1
2013-05-23 12:21
求翻譯：A molybdenum height of 42 nm was chosen because itresults in the highest second-order diffraction efficiency for thesmallest period of p0= 48 nm, as is seen from figure 2(i).The simulations showing the transmittance of the first fewdiffraction orders as a function of fill factor at a height h =42 nm for p0= 48 nm and p是什么意思？ 待解決
 懸賞分：1
- 離問題結(jié)束還有
A molybdenum height of 42 nm was chosen because itresults in the highest second-order diffraction efficiency for thesmallest period of p0= 48 nm, as is seen from figure 2(i).The simulations showing the transmittance of the first fewdiffraction orders as a function of fill factor at a height h =42 nm for p0= 48 nm and p
問題補(bǔ)充： |
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2013-05-23 12:21:38
正在翻譯，請等待...
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2013-05-23 12:23:18
正在翻譯，請等待...
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2013-05-23 12:24:58
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2013-05-23 12:26:38
鉬高度為 42 nm 的選擇是因?yàn)?p0 高射段二階衍射效率最高的 itresults = 48 nm，從圖 2(i) 所示。模擬顯示透過率的第一次的 fewdiffraction 訂單作為函數(shù)的填充因子在高度 h = 42 nm 為 p0 = 48 nm 和 p0 = 72 nm 光柵分別是 shownin 數(shù)字 5(a) 和 (b)。要分別為 2%和 4%，可以找到興趣標(biāo)記與黑色虛線%
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2013-05-23 12:28:18
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