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關注：1
2013-05-23 12:21
求翻譯：從上圖的分析中可以得到曲面的最小半徑為1.237，也就是說最大能薄殼（shell1）1.237的平均料厚。假如現在的模型要shell 1.5料厚的話就會造成失敗。那我們要采取什么樣的措施才能讓模型最終生成1.5mm的料厚呢？解決方法有兩種，但是都有個前提，得到的料厚不再是等料厚的了，這是因為本身曲面曲率的原因，模型已經不可能可以shell等料厚了，我們需要對這個部分作特殊處理是什么意思？ 待解決
 懸賞分：1
- 離問題結束還有
從上圖的分析中可以得到曲面的最小半徑為1.237，也就是說最大能薄殼（shell1）1.237的平均料厚。假如現在的模型要shell 1.5料厚的話就會造成失敗。那我們要采取什么樣的措施才能讓模型最終生成1.5mm的料厚呢？解決方法有兩種，但是都有個前提，得到的料厚不再是等料厚的了，這是因為本身曲面曲率的原因，模型已經不可能可以shell等料厚了，我們需要對這個部分作特殊處理
問題補充： |
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2013-05-23 12:21:38
Can be obtained from the above analysis, the minimum radius of the surface to 1.237, meaning that the maximum shell (shell1) 1.237, the average material thickness. Now model the shell 1.5 feed thick it will cause a failure. That we have to take what measures to make the model the resulting material
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2013-05-23 12:23:18
From the above analysis can be curved in the minimum radius to 1.237 , that is the maximum that can thin Shell (Shell 1) The average 1.237 meter thick. Now if you want to shell the model 1.5 meter thick would be caused to fail. Then we have to take what measures to take to get the resulting model of
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2013-05-23 12:24:58
May obtain the curved surface minimum radius from in on chart analysis is 1.237, in other words, can the thin shell (shell1)1.237 average material be thick most greatly.If the present model wants the shell 1.5 material thick speeches to be able to create the defeat.What type then we do want to adopt
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2013-05-23 12:26:38
正在翻譯，請等待...
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2013-05-23 12:28:18
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