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關注：1
2013-05-23 12:21
求翻譯：當給定2%（換算成電流是0.34MA）的開啟角度時，定位器不能執行動作，只有開啟角度值給定高于4%（換算成電流是0.68MA）時定位器才執行動作是什么意思？ 待解決
 懸賞分：1
- 離問題結束還有
當給定2%（換算成電流是0.34MA）的開啟角度時，定位器不能執行動作，只有開啟角度值給定高于4%（換算成電流是0.68MA）時定位器才執行動作
問題補充： |
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2013-05-23 12:21:38
When given 2% (converted into current 0.34ma) in the opening angle, the locator can not perform the action, only to open the angle values ??given above 4% (converted into current 0.68ma locator) to perform an action
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2013-05-23 12:23:18
When a given 2% (0.34 is converted to a current MA) when the opening angle, positioning is not action, it is only open for a given angle value higher than 4 per cent (0.68 is converted to a current position when MA) server is executing the move.
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2013-05-23 12:24:58
正在翻譯，請等待...
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2013-05-23 12:26:38
When given 2% (conversion into an electric current is 0.34MA) opening angle, locators could not perform the action, only the opening angle values given above 4% (conversion into an electric current is 0.68MA) Locator only when performing an action
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2013-05-23 12:28:18
When when assigns 2% (to convert electric current is 0.34MA) the opening angle, the locator cannot carry out the movement, when the opening angle value assigns is higher than 4% (to convert electric current is 0.68MA) the locator only then to carry out the movement
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