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關(guān)注:1
2013-05-23 12:21
求翻譯:假設(shè)S為已求得最短路徑的終點(diǎn)的集合,則可證明:下一條最短路徑(設(shè)其終點(diǎn)用戶為x)或者是路線(i,x),或者是中間只經(jīng)過S中的頂點(diǎn)而最后到達(dá)用戶X的路徑。這可用反證法來證明。假設(shè)此路徑上有一個(gè)頂點(diǎn)不在s中,則說明存在一條是什么意思?![]() ![]() 假設(shè)S為已求得最短路徑的終點(diǎn)的集合,則可證明:下一條最短路徑(設(shè)其終點(diǎn)用戶為x)或者是路線(i,x),或者是中間只經(jīng)過S中的頂點(diǎn)而最后到達(dá)用戶X的路徑。這可用反證法來證明。假設(shè)此路徑上有一個(gè)頂點(diǎn)不在s中,則說明存在一條
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2013-05-23 12:21:38
Suppose S is the shortest path has been obtained by the end of the set, you can prove that: the next shortest path (set up its end users x) or route (i, x), or only after the middle of the vertices in S to reach the final User X's path. This can be reductio ad absurdum to prove. Suppose there is a v
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2013-05-23 12:23:18
S assumptions have been obtained for the shortest path to the finish line will prove a collection: The next section (located the shortest path to its destination X users (i) or a line, X), or a middle S only after the peak in the path of X users finally arrived. This can be used to prove the contrar
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2013-05-23 12:24:58
正在翻譯,請等待...
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2013-05-23 12:26:38
Suppose that s is the collection has been seeking the end of the shortest path, you can prove that the next shortest paths (at its end users for x) or route (i,x), or only after the s in the vertex and the last in the middle path to reach the user x. This absurdity can be used to prove it. Assume th
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2013-05-23 12:28:18
Suppose S is the shortest path has been obtained by the end of the set, you can prove that: the next shortest path (set up its end users x) or route (i, x), or only after the middle of the vertices in S to reach the final User X's path. This can be reductio ad absurdum to prove. Suppose there is a v
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